Monday, September 29, 2014

Van de Graff Generator Cage, Bed of Nails, ActivPhysics

Van de Graff Generator Cage

Pieces of aluminum foil were attacted by a string and hung over a cage.  That cage was then placed on top of a van de graff generator which gave the cage a huge negative charge.  We were asked to predict what would happen to the pieces of aluminum foil when the generator was turned on.  We predicted that when the generator were turned on that both of the pieces of aluminum foil (inside and outside of the cage) would move away from the cylinder.  The answer was that only the pieces of aluminum foil on the outside of the cage moved away.  This is because of shielding; conductors want to be as far away as possible so that the net charge inside the cage is zero.  It is now known that the electric field inside a conductor is always zero because of shielding!























Bed of Nails

The bed of nails represented an electric field.  When the metal wire was placed on top of the electric field, the intensity of the field was great.  As the metal wire tilted at an angle away from the bed of nails, the intensity of the electric field got smaller and smaller until the metal wire and the bed of nails were perpendicular to each other and the effect of the electric field on the metal wire was zero which explains why the equation of the flux (The number of electric field lines through an area) is defined as E A cos (theta). 




ActivPhysics

It was concluded that there were 5 lines per charge added
+ 4 Charges

+1 Charge

-1 Charge

Positive and negative charge





Electric Field Hockey



Wednesday, September 24, 2014

gravitational field, electric field model, electric field charges, ActivPhysics

Gravitational field -- analogous to electric field


The electric field is almost identical to the gravitational field.  We showed this by taking four statements, morphing them by changing a few words, and making them from statements about gravity to statements about the electric field!











Electric Field Model


Positive electric field buldges outward and negative concaves inward.  When a positive charges moves inward towards negatively charged electric field, the positive charge falls to the middle of the negative electric field.  Now with positive and negative electric field next to eachother: when you put the positive charge on top of positively charged electric field it will be repelled from the positively charged field and towards negative.





















Electric Field Vectors from Two Point Charges



Two charges of opposite sign were placed on a graph and four points were also placed on the graph and we were to find the electric field at the four points.  The equation we used to find the electric field was kq/r^2.  We then made a spreadsheet on excel and calculated the electric field at distences of .5 cm to 10 cm.  We then found the electric field from the positive charge and the negative charge in the x and y directions by looking at the spreadsheet and filling in the value of the electric field at that certain distance.  After we found all of the electric fields, we added them together to find the final sum of all the electric fields.  It was found that all of the y parts of the electric field canceled and the resultant electric field was 52600 N/C in the x direction.  




















Electric Field Charges from a Uniformly Charged Rod


A uniformly charged rod is placed with a point is placed underneath the rod and to the side of the rod.  The rod is split into ten pieces so it is easier to calculate the net electric field.  The electric field is drawn from the two points to the ten sections on the rod.  Then the electric field is calculated using the equation kQ/r^2.  The values of r and the equation were put into a spreadsheet and then the sum was calculated to find the resultant electric field at the two points.  For the point next to the rod, the resultant electric field was accurate because all of the electric field lines lie in the x axis.  As for the point beneath the rod, it is more difficult to calculate the net resultant electric field because the radius had to be calculated by the sqrt of  (X^2 + Y^2).  A better way of finding the electric field for the point underneath the bar is by using an integral.  When we found the electric field by calculating all 10 points and sum it up we got it to be  5.95 x10^4 and when we calculated it using an integral, we found it to be 6.0 x10^4 giving us a .47% error which is very good.  The little bit of error we got was due to the fact we had to calculate the radius and that we only cut the rod into 10 pieces instead of more.



















ActivPhysics

ActivPhysics answers for electric fields



Monday, September 22, 2014

Balloon and electric interactions, tape and electric interactions, electric force law, experiments with van de graff generator




Balloon and Electric Interactions



We were asked what we thought would happen when to a balloon when placed on a wall after a pelt of fur were rubbed on the balloon.  Our prediction of this situation was that the balloon would slide down slowly because although there were some electric attraction between the wall and the wall, that the gravity acting on the balloon would make it slide down the wall.  The result was that the balloon actually stuck to the wall and didn’t fall at all.  What happened was that when the fur and the balloon came in contact, the balloon stole the negative charge from the fur so when the balloon touched the wall it stuck.  





The balloon sticks to the wall because the negative charge on the balloon forces the negative charges on the wall to move away creating an induced positive charge which attracts the negative charge from the balloon.  The same thing will happen between the balloon and the wall if the balloon is rubbed with a piece of silk or even your hair!









Tape and Electric Interactions

First we stuck two different pieces of tape onto the table, pealed the off, and brought the two non-sticky sides of the tape together.  When brought together, the two pieces of tape repelled each other.  This is because the tape stole positive charges from the table so when they were brought together the same sides with the same charge repelled each other.  It could also be seen that they closer the two pieces of tape approached one another, the more they repelled one another.  Next, two pieces of tape were stuck to the table and another two pieces of tape were stuck on top of the pieces on the table.  First we pulled both strips off the table and then the two pieces were pulled apart.  When the two pieces that were on the table were brought together they repelled a lot, when the two top strips that were connected to the bottom strips they repelled slightly, and when the top pieces were brought to the bottom pieces they were attracted to each other.  The tapes that were repelled from each other had the same charge and the tapes that attracted each other had opposite charges.  These results prove the hypothesis that was given at the start of the experiment, there are two types of electrical charges known as positive and negative.






Electric Force Law

We began this experiment with a 4A question and were asked to find the angle that a ball hanging on a string has with the vertical after a charged ball repelled the hanging ball.  The angle was found to be sin^-1(x2/L).  Now we are told that a child sits on a swing with mass m and that this child is being pulled horizontally so that the string remains length l and at the same theta found in the charged ball problem.  The force the child is being pulled out at was found to be F = tan (theta) *m*g and after substituting theta, we found the force on the child to be F = tan ( sin^-1(x2/L))*m*g.  






A video was given to us to use as data on logger pro that was the charged ball hanging on the string and the charged ball on a stick that repelled the ball on the string and made the string approach theta.  The video was went through frame by frame and data points were taken on the video for each ball that were later shown on logger pro.  After all the points were on logger pro, two new calculated columns were created.  The first column was separation distance between the hanging ball and the ball on the stick which was calculated as (x2-x1).  The next column calculated was the electrical force from the ball on the stick on the hanging ball which we calculated earlier and is the same force as the small child   F = tan ( sin^-1(x2/L))*m*g.  After we had our two calculated columns, we made a plot of electrical force vs separation distance. 




 From our graph, we were able to show that the electric force is inversely proportional to the square of the distance between the charges because not only did our power fit equation of Ar^B give us a B value of -2.088, but when we fit our graph to the equation A/x^2 it fit almost perfect.  In fact our B value from the power fit equation only showed a 4.4% difference from the true value of 2. Next, we assumed that the charge on both of the balls was the same.  With taking two values from our graph, the force and the separated distance, we calculated the charge of the balls which we found to be 3.23x10^-7 .  



We then stated that if the charge of the hanging ball were to be half of the charge of the ball on the stick.  We calculated the charge of the ball on the stick to be 4.57x10^-7 so if the charge of the hanging ball were to be half of that then the charge on the hanging ball would be 2.9x10^-7.  As for the charge on the balls, this cannot be determined because although you know that the signs are the same (because the balls repel), there is not enough information to determine if they are positive or negative. Especially because when you solve for q its under a square root so the answer could be positive or negative.



Van de Graff Generator


How the Van de Graff Works


















The Van de Graff Generator has a rubber band that spins in a circle.  The band rotates down to the bottom of the generator and rubs a pad where it picks up electrons.  The band then continues to the top and rubs against the wires connected to a metal pole and the charge is transferred from the band to the wires.

Hair sticking up on end

When a wig is placed on top of the generator, the electrons are transferred from the generator to the ends of the hair.  Because the ends of the hair are now charged with the same sign of charge, they repel eachother which gives the hair the effect of it sticking up on its ends.  When you place your hand on the hair, you hand absorbs the electrons and the hair falls down.  Once you move your hand the electrons go back to the end of the hair and it sticks back up.
















Franklin Motor

A Franklin motor is set on top of a van de graff generator and the electrons that are generated in the van de graff are transferred to the Franklin motor.  The charge accumulates on corners and the large charge accumulation at those point makes the Franklin motor spin because the charges are exiting the generator at the ends of the rod.




























Ribbon

Ribbon was placed on top of the van de graff generator and when the electrons were transferred form the de graff generator to the ends of the ribbon, the ribbon stood up on its end.  The reason the ribbon stood away from the generator is because the generator is releasing electrons and the ends of the ribbons are filled with electrons, making them repel one another.



Storm Ball

The storm ball is filled with some type of noble gas. A voltage is applied to the center of the storm ball. The center is an electrical conductor used to make contact with a nonmetallic part of a circuit. By applying the voltage to it, and electric field between the center and the glass globe is made. This electric field allows electrons to move through the gas and towards the glass of the ball.  If you touch the plasma ball, all of the electrons will go through you to the ground. You see only one big spark inside the ball where you put your hand. 








Wednesday, September 17, 2014

Sterling engine and Climbing Stairs

Sterling Engine

The way a sterling engine works is a piston moved the air inside the cylinder from the hot side to the cold side.  The gas expands when it is on the hot side and pushes up the piston and it contracts and pulls the piston down when it is on the cold side.  We put a hot water reservoir on the bottom of the sterling engine and a cold reservoir on top by placing ice cubes on top of the engine. The bigger the temperature difference between the reservoirs, the quicker it will turn.  All sterling engines have low cycles per second which in turn makes them have low power, so they won’t do a good job running a car because the power to weight ratio is low.  These engines are also used for solar energy production.  A big plate painted black is outside of the ground so the sun shines on it to warm it up and other half is underground to stay cool.  Efficiency of these sterling engines are 1 – Th/Tc.  The average ground temp is approx. 10 degrees Celsius and the sky is about 40 degrees Celsius so the efficiency is 1- 270/300 which is .1 or 10% efficiency.  Efficiency improves with the bigger temp difference, but what this engine creates is creates mechanical work and so you have to put it through a generator to convert it to energy



























Climbing Stairs





We were asked how many floors per minute you would have to climb to generate 760 Watts.  We determined that a floor is approximately 5 meters by sticking a meter stick through the roof until it hit the bottom of the floor above us.  Assuming we weighted 100 kg and that one floor was equal to 5 meters , we found that you would have to walk 9.30 floors per minute to generate 760 Watts.  Although I could probably run one or two sets of stairs in what seems like no time, I don’t believe that I would be able to keep that up for 9 floors and keep my time under a minute.